Math, asked by hbcreation506, 8 months ago

A dice thrown once find the probability of (I) a number less than 4 (ii) a number greater than 4 (III) a number not less than 3​​ [ please send a photo ]​

Answers

Answered by Anonymous
5

Answer:

(I) 1/2

(II) 1/3

(III) 1/3

Step-by-step explanation:

(I) probability = No. of possible outcomes / total no. of outcomes

  In a dice there are numbers from 1 to 6

therefore number less than 4 is 1,2 and 3

so probability = 3/6

                       = 1/2

(II) probability = No. of possible outcomes / total no. of outcomes

    In a dice there are numbers from 1 to 6

    Numbers greater than four is 5 and 6

   Probability = 2/6

                      = 1/3

(III) probability = No. of possible outcomes / total no. of outcomes

    In a dice there are numbers from 1 to 6

   Number less than 3 are 1 and 2

   Probability = 2/6

                      = 1/3

Answered by malikuttam80
0

Step-by-step explanation:

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