Question

a dice thrown once . the probability of getting the square of the number appearing on the dice to be a multiple og 9, is

Answer 1

Total outcome =6

Square of numbers =(1) ^2,(2)^2,(3)^2,(4)^2,(5)^2,(6)^2 =1,4,9,16,25,36

Multiple of 9 = 9, 36 =2

Let (A) be the event of getting multiple of 9

P (A) = F. O/ T. O = 2/6 =1/3