A dice thrown twice, find the probability of getting five at least once
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Hey mate .........
Total outcomes =6×6=36
Favourable putcomes /Total outcomes......
1/36....
mark me brainliest
Total outcomes =6×6=36
Favourable putcomes /Total outcomes......
1/36....
mark me brainliest
Answered by
0
Answer:
Step-by-step explanation:
5 not exist in a die.
The probability of impossible event is 0
We can prove it.
P(5)=0/6=0 hence proved
Here we go✌
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