Question

a dice thrown twice what is the probability that 5 will not come up either time​

Answer 1

Answer:

Step-by-step explanation:

Total event =6×6 =36

Events of getting 5 are = (5,1),( 5,2),( 5,3),( 5,4),( 5,5),( 5,6),(1,5),(2,5),(3,5), (4,5),( 6,5)

probability of getting getting 5 =11/36

Probability of not getting 5 =1-(11/36) =25/36

probability of getting. 5 exactly one time is =10/36

Answer 2

total outcome = 36

favourable out comes = 11

let(A) the event of not getting 5 either time

P(A)= N(A)/ N(S)

= 11/36

i:e 11/36 is probablity of not getting 5 either time