Question

a die has 6 faces marked by the given numbers as shown below 1, 2 ,3, -1 ,-2 ,-3 the die is thrown once what is the probability of getting the smallest integer

Answer 1

Answer:

smallest integer = -3

so -3/total no = -3/6 = -1/2 = we can say it as 1/2

Answer 2

Answer:

1/6

Step-by-step explanation:

If S is the sample space then

S={1,2,3,-1,-2,-3}

therefore, n(S)= 6

event A: PROBABILITY OF getting the smallest integer

A=(-3)

therefore, n(A)=1

therefore, P(A)=n(A)/n(S)

=1/6

hope it helps