Question

A die has six faces (0,0,1,1,6,6) two such dice are thrown together are total score
(i) How many different scores are possible
(ii) What is the probability of getting a total of 7

Answer 1

Step-by-step explanation:

Given, a die has its six faces marked {0, 1, 1, 1, 6, 6}

∴ Total sample space, n(S) = 36

(i) Number of favorable outcomes are (0,0),(0,1),(0,6),(1,0),(1,1),(1,6) ,(6,0),(6,1),(6,6).

The different score which are possible are 6 scores i.e., 0,1,2,6,7 and 12.

(ii) Let E = Event of getting a sum 7 = {(1,6),(1,6),(1,6),(1,6),(1,6),(1,6),(6,1),(6,1),(6,1),(6,1)(6,1)(6,1)}

∴ n(E) = 12

Answer 2

Answer:

diffrent scores: 12,2,0,7,6,1

Step-by-step explanation:

I SAID DIFFRENT SCORES BASED ON ALL POSSIBILITIES IT COULD HAVE.

PROBABILITY OF GETTING 7: TO GET 7 ON ONE DICE THERE SHOULD BE 6 AND ON OTHER 1. THERE IS LESS PROBABILITY OF 7I HOPE IT HELPED U. THANKS