Question

A die is loaded so that probability of an even number twice the probability of an odd number. Even numbers are equally likely as well as odd numbers are equally likely.find the probability that an even number appers, A prime no. appears uppermost, An odd no. appears uppermost, A perfect square appears uppermost.​

Answer 1

Answer:

4/9

Explanation:

Number of dice = 1 (Given)

Total number of faces = 6 (Given)

A die is rolled such that each even number occurs twice and odd number occurs once.

Therefore the total possible sample space will be = {1,1,2,3,3,4,5,5,6}

Thus n(s)=9

P(Greater than 3) to occur.

Hence, the number of favorable outcomes n(E)={4,5,5,6}

= 4

Required probability = n(e)/n(s)

= 4/9