Question

A die is numbered as V1, V2, V3,
V5 & V6. Find the probability of getting
(i) Irrational number (ii) an even number.​

Answer 1

Answer:

(I)2/3

(II)=1/6

Step-by-step explanation:

(I)

out of the 6 numbers, we know that√2,√3,√5&√6are irrational.

so P(irrational) = 4/6=2/3

(II)

we know that only √4=2is even

so P(even)=1/6

Answer 2

Step-by-step explanation:

Sample space (S)= ( √V1,√V2,√V3,√V4,√V5,√V6)

Sample point n(S)= 6

i) let the event of getting irrational number be A.

Now,

A=( √V1,√V2,√V3,√V4,√V5√V6)

n(A)=6

Probability of getting event A:

p(A)= n(A)/n(S)

= 6/6

=1

ii) let the event of getting even number be B:

Now,

B=( 1,2)

n(B)=2

Probability of getting event B:

p(B)= n(B)/n(S)

= 2/6

=1/3

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