Question

A die is numbered in such a way that its faces show the numbers 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Make the table showing the outcomes. What is the probability that the total score is (i) 6 (ii) at least 8?​

Answer 1

Answer:

We know that,

Probability = Number of possible outcomes / Total number of outcomes

+ 1 2 2 3 3 6

1 2 3 3 4 4 7

2 3 4 4 5 5 8

2 3 4 4 5 5 8

3 4 5 5 6 6 9

3 4 5 5 6 6 9

6 7 8 8 9 9 12

Total number of possible outcomes = 6 × 6 = 36

(i) Number of possible outcomes when the sum is even = 18

The probability that the total score is even = Number of possible outcomes/Total number of outcomes

= 18/36

= 1/2

(ii) Number of possible outcomes when the sum is 6 = 4

Probability of getting the sum as 6 = Number of possible outcomes / Total number of outcomes

= 4/36

= 1/9

(iii) Number of possible outcomes when the sum is at least 6 (greater than 5) = 15

Probability of getting the sum at least 6 = Number of possible outcomes / Total number of outcomes

= 15/36

= 5/12

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Step-by-step explanation:

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Answer 2

The Answer is in Attachment

Hope it Help you