Math, asked by kanishkasmkp, 11 months ago

a die is rolled 250 times and its outcomes are recorded as follows:

Outcomes 1 2 3 4 5 6
Frequency 40 45 35 38 52 40
Find the probability of getting
a)An even number
b)An multiple of five

Answers

Answered by pratham280604
15

Step-by-step explanation:

a) No. of favorable outcome= 40+38+40=118

   total outcome=250

   probability= 118/250=59/125

b) No. of favorable outcome= 52

   probability= 52/250=26/125

Answered by VineetaGara
5

Given,

A dice is rolled for = 250 times

Frequency of occurrence of 1 = 40

Frequency of occurrence of 2 = 45

Frequency of occurrence of 3 = 35

Frequency of occurrence of 4 = 38

Frequency of occurrence of 5 = 52

Frequency of occurrence of 6 = 40

To find,

a) The probability of getting an even number

b) The probability of getting a multiple of 5

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

The probability of occurrence of a favorable event = P (favorable event)

= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)

= (Total number of occurrence of the favorable event) / (Total number of trials)

As per the given question;

The favorable event is the occurrence of an even number, that is 2, 4 and 6.

And, the total number of trials = 250

Now,

The probability of getting an even number

= P(getting an even number)

= {(frequency of occurrence of 2) + (frequency of occurrence of 4) + (frequency of occurrence of 6)} / (total number of trials)

= { 45 + 38 + 40 } / 250

= 123/250

=> P(getting an even number) = 0.492

Now,

The favorable event is the occurrence of a multiple of 5.

The probability of getting a multiple of 5

= P(getting multiple of 5)

= 52/250

= 0.208

Hence, the probability of getting an even number is equal to 0.508 and the probability of getting a multiple of 5 is equal to 0.208.

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