A die is rolled . find the probability that an even number is obtained .
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No. of required events= 3(2,4,6)
Total no.of possible events=6
Probability=3/6=0.5
Total no.of possible events=6
Probability=3/6=0.5
Answered by
2
out of six numbers present in the die even numbers are 2,4,6
so
probability=number of favorable outcomes/total number of outcomes
no. of favourable outcomes=3(2,4,6)
P(E)=3/6=1/2
so
probability=number of favorable outcomes/total number of outcomes
no. of favourable outcomes=3(2,4,6)
P(E)=3/6=1/2
abhishek465:
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