Question

A die is rolled once what is the probability that the number on top will be a) odd number b) greater than 5 c) A multiple of 3​

Answer 1

Answer:

S={1,2,3,4,5,6}

n(s)=6

event A:odd number

A={1,3,5}

n(A)=3

p(A)=n(A)/n(s)

=3/6

=1/2

event B:greater than 5

B={6}

n(B)=1

p(B)=n(B)/n(s)

=1/6

eventC:A multiple of 3

C={3,6}

n(C)=2

p(C)=n(C)/n(s)

=2/6

=1/3

Answer 2

Answer:

Sicne the die has 6 numbers.

Step-by-step explanation:

Probability of getting odd number=

Probability of getting odd number= Favourable outcomes/Total outcomes--1

Favourable outcomes(i.e odd numbers till 6)=3

Total outcomes=6

According to the Probability=3/6. (From 1)

Simplifying=1/2

Hence the probability of getting odd number is 1/2.

b) Favorable outcomes=1

Total outcomes=6

According to the Probability=1/6. (From eq.1)