A die is rolled three times. the probability that sum is 10 is
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All possible cases in case a die is rolled thrice = 6^3 =216
(6,3,1) (6,2,2) (6,1,3) (5,4,1) (5,3,2) (5,2,3) (5,1,4)
(4,5,1) (4,4,2) (4,3,3) (4,2,4) (4,1,5) (3,6,1) (3,5,2)(3,4,3) (3,3,4) (3,2,5) (3,1,6) (2,6,2)(2,5,3)(2,4,4)(2,3,5) (1,6,3)(1,5,4)(1,4,5)(1,3,6)
thus, the probability is
=> 26/216
Hope it's helpful
====================================
All possible cases in case a die is rolled thrice = 6^3 =216
(6,3,1) (6,2,2) (6,1,3) (5,4,1) (5,3,2) (5,2,3) (5,1,4)
(4,5,1) (4,4,2) (4,3,3) (4,2,4) (4,1,5) (3,6,1) (3,5,2)(3,4,3) (3,3,4) (3,2,5) (3,1,6) (2,6,2)(2,5,3)(2,4,4)(2,3,5) (1,6,3)(1,5,4)(1,4,5)(1,3,6)
thus, the probability is
=> 26/216
Hope it's helpful
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