A die is rolled thrice. what is the probability that the sum of the rolls is atleast 5.
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1/6 is the probability for atleast 5
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Number of events of getting a total of less than 5 = 4
i.e. (1, 1, 1), (1, 1, 2), (1, 2, 1) and (2, 1, 1).
Therefore, probability of getting a total of less than 5
P(E3) = Number of favorable outcomes/Total number of possible outcome
P(E3) = 4/216
P(E3) = 1/54
so, probability of getting a total of at least 5 = 1 - P (getting a total of less than 5)
= 1 - 1/54
= (54 - 1)/54
= 53/54 ANS
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