A die is rolled twice. Find the probability of getting sum 8
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Given : a die is rolled twice
To find : probability of getting the sum of resultants as 8
Solution:
a die is rolled twice
Dice has 1 to 6 number
if rolled twice possible outcomes = 6 * 6 = 36
n(S) = 36
Sum of resultant as 8
2 + 6 , 3 + 5 , 4 + 4 , 5 + 3 , 6 + 2
n(E) = 5
probability of getting the sum of resultants as 8 = n(E)/n(S)
= 5/36
5/36 is the probability of getting the sum of resultants as 8
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