A die is rolled twice find the probabilty of getting sum 7 atleast once
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(Sum of 7) = {4+3, 3+4, 6+1, 1+6, 5+2, 2+5} = 6
(At Least one 5) = {1+5, 2+5, 3+5, 4+5, 6+5, 5+1, 5+3, 5+4, 5+5, 5+6} = 10
so the answer will be 16/36 =
4/9
(At Least one 5) = {1+5, 2+5, 3+5, 4+5, 6+5, 5+1, 5+3, 5+4, 5+5, 5+6} = 10
so the answer will be 16/36 =
4/9
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