a die is rolled. what is the probability that the number appearing on upper face is greater than 4?
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Answered by
12
Answer:
s={1,2,3,4,5,6}
n(S)=6
event A=upper face having greater than 4
A={5,6,}
n(A)=2
p(A)=n(A)/n(s)
=2/6
=1/3
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Answered by
1
Step-by-step explanation:
s=(1,2,3,4,5,6,). n(s)=6
E=(5,6). n(s)=2
p(E)=n{E}=2
n{S}=6
2*1=1
2,6=3
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