A die is throum omce.f md probability of getting .(1)a parirme number .(2)a number betweem 2amd5.
Answers
Step-by-step explanation:
Since a dice is thrown once.
Outcomes = 1,2,3,4,5,6
No. of outcomes = 6
1) Event = getting a prime number
No. of event = 3 ( 2, 3,5)
P (getting a prime no.) = No.of event/ total outcomes
= 3/6 = 1/2
2) Event = getting a number between 2and 5
No. of event = 2 (3,4)
P (getting a no. between 2 and 5)
= No.of event/ total outcomes
= 2/6 = 1/3
Answer:
(i) 1/2
(ii) 1/3
Step-by-step explanation:
The total outcomes are:
1, 2, 3, 4, 5 and 6.
(i) Prime numbers in a die --> 2, 3 and 5 (3 primes)
Total outcomes --> 1, 2, 3, 4, 5 and 6 (6 outcomes)
Probability --> (Favourable outcomes)/(Total outcomes)
=> 3/6 => 1/2 is the probability of getting a prime number in one throw of a die.
(ii) Numbers between 2 and 5 in a die --> 3 and 4 (2 outcomes)
Total outcomes --> 1, 2, 3, 4, 5 and 6 (6 outcomes)
Probability --> (Favourable outcomes)/(Total outcomes)
=> 2/6 => 1/3 is the probability of getting a number between 2 and 5 in one throw of a die.