a die is throw n once.find the probability of getting (i)7,(ii)4
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Step-by-step explanation:
1st 0/6
2nd =1/6
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a die is thrown
thus The sample space is
S={123456}
n(S)=6
let A be the event of getting 7
A={ }. n(A)=0
p(A)= n(A)/n(S)=0/6=0
let B be the event of getting 4
B={4} n(B)=1
p(B)=n(A)/n(S)=4/6=2/3
hope it will help you Mark it as brainliest
thus The sample space is
S={123456}
n(S)=6
let A be the event of getting 7
A={ }. n(A)=0
p(A)= n(A)/n(S)=0/6=0
let B be the event of getting 4
B={4} n(B)=1
p(B)=n(A)/n(S)=4/6=2/3
hope it will help you Mark it as brainliest
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