A die is thrown 1 calculate the probability getting a number less than 3
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s={1,2,3,4,5,6}
n (s)=6
Event A getting less then 3 number
A={1,2}
n (A)=2
p (A)=n (A)/n (S)
p (A)=2/6
p (A)=1/3
Hope it will correct. ...
dhanrajsatare786:
Dhanraj
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Answer:
S = (1,2,3,4,5,6)
n(s)=6
Event = getting a number less than 3
= (1,2)
n(a)=2
p(a)= 2/6
p(a)= 1/3
Step-by-step explanation:
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