Question

a die is thrown 256 times. an even digit turns up 150 times. then the die is​

Answer 1

Answer:

256-150=

106

$\frac{Number \: of \: favourables outcomes }{total \: of favourables outcomes }$

$\frac{150}{256} = 1.7$

Answer 2

Given,

a die is thrown 256 times and an even digit turns up 150 times.

n = 256

To Find,

z=?

Solution,

to find z we have to apply the formula z = ( x - μ )/ σ

where μ is the mean and σ is the standard deviation.

probability of even digit is

$p=\frac{number of favourable outcomes}{total of favourable outcomes}$

$p= \frac{150}{256}$

$p= \frac{75}{128}$

p = 0.5859375

now, find the mean(μ = np) and standard deviation(σ = sqrt[n x p (1-p)] .

mean (μ) = np

              = 256 x (75/128)

              = 150

standard deviation (σ) = sqrt[n x p (1-p)]

                                     = sqrt[256 x (75/128)(1-(75/128))]

                                     = 62.109375

now, find [z = ( x- μ) / σ ]

z = ( x- μ) / σ

  = (256 - 150) / 62.109375

  = 1.70666 (approx)

$z= 1.7$

Hence the value of z is 1.7