A die is thrown 3 times, if the first throw is a four, then find the probability of getting 15 as a sum.
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Probability that first throw is 4 given that sum is 15
= P(first throw = 4, sum = 15)/ P(Sum = 15)
=[1/6×2×1/36]/10/216
=2/10=1/5.
Probability that sum is 15 given that first throw is 4
= P(first throw = 4, sum = 15)/ P(First throw is 4)
=[1/6×2×1/36]/1/6
=2/36=1/18
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Answer: can u pls mark me brainliest pls
Probability that first throw is 4 given that sum is 15
= P(first throw = 4, sum = 15)/ P(Sum = 15)
=[1/6×2×1/36]/10/216
=2/10=1/5.
Probability that sum is 15 given that first throw is 4
= P(first throw = 4, sum = 15)/ P(First throw is 4)
=[1/6×2×1/36]/1/6
=2/36=1/18
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