Question

A die is thrown at random. Find the probability of getting (i) 2 ,(ii) a number less than 3, (iii)a composite number , (iv) a number not less than 4

Answer 1

Answer:

Step-by-step explanation:

$P(E)=\frac{n(e)}{n(s)}$

1) n(e)=1

n(s)=6

P(e)=1/6

2) n(e)= 2 (1,2)

n(s)= 6

P(E)=2/6= 1/3

3)  n(e)=2 (4,6)

n(s)=6

P(E)=2/6=1/3

4) n(e)=3(4,5,6)

n(s)=6

P(E)=3/6=1/2