Question

a die is thrown at random.find the probability of getting: i) an even prime number ii) a number less than 3 iii) a composite number iv) a number not less than 4 v) a number between 2 and 6​

Answer 1

Answer:

I think so it is composite number

Answer 2

Answer:

i)chance of getting even prime number=1/6

ii)2/6=1/3

iii)2/6=1/3

iv)2/6=1/3

v)3/6=1/2

Step-by-step explanation:

i)The only even prime number in all of the list of prime nos is 2. there is only one even prime no. between 1 and 6 that is 2, so that is. 1/6

ii)less than three means, three is not included.so the leftover numbers are 1 and 2 that is 2 nos. = 2/6=1/3

iii)the composite nos btwn 1 n 6 is 4 and 6 that is 2 nos.=2/6=1/3

iv)1,2,3,4 not included; leftovers are 5 n 6 that is 2 nos=2/6=1/3

v) 1,2 and 6 not included. leftovers are; 3,4 n 5 that is 3 nos=3/6=1/2

*I HAVE NOT STUDIED PROBABILITY YET, SO MY ANSWERS MIGHT BE WRONG. PLS FORGIVE ME*