a die is thrown, find the probability of getting a number greater than 4
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total no. of outcomes = 6 {1,2,3,4,5,6}
favourable no. of outcomes of getting no. greater than 4 = 2 {5,6}
P(x) = favourable outcomes / total outcomes
P (getting a number greater than 4 ) = 2/6 = 1/3
favourable no. of outcomes of getting no. greater than 4 = 2 {5,6}
P(x) = favourable outcomes / total outcomes
P (getting a number greater than 4 ) = 2/6 = 1/3
shubhrashreenayak:
i want it to be done by process
is it OK ????
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1/3 is probability of getting a number greater than 4
i want it be done by process
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