Question

A die is thrown. Find the probability of getting:
(i) a prime number
(ii) 2 or 4
(iii) a multiple of 2 or 3
(iv) an even prime number
(v) a number greater than 5
(vi) a number lying between 2 and 6

Answer 1

Answer:

(i) Total no of possible outcomes = 6 {1, 2, 3, 4, 5, 6} E ⟶ Event of getting a prime no. No. of favorable outcomes = 3 {2, 3, 5} P(E) = (No. of favorable outcomes)/(Total no. of possible outcomes) P(E) = 3/6 = 1/2 (ii) E ⟶ Event of getting 2 or 4. No. of favorable outcomes = 2 {2, 4} Total no. of possible outcomes = 6 Then, P(E) = 2/6 = 1/3 (iii) E ⟶ Event of getting a multiple of 2 or 3 No. of favorable outcomes = 4 {2, 3, 4, 6} Total no. of possible outcomes = 6 Then, P(E) = 4/6 = 2/3 (iv) E ⟶ Event of getting an even prime no. No. of favorable outcomes = 1 {2} Total no. of possible outcomes = 6 {1, 2, 3, 4, 5, 6} P(E) = 1/6 (v) E ⟶ Event of getting a no. greater than 5. No. of favorable outcomes = 1 {6} Total no. of possible outcomes = 6 P(E) = 1/6 (vi) E ⟶ Event of getting a no. lying between 2 and 6. No. of favorable outcomes = 3 {3, 4, 5} Total no. of possible outcomes = 6 P(E) = 3/6 = 1)2

Answer 2

Answer:

1.1/3

2.1/3

3.2/3

4.1/6

5.1/6

6.1/2