Question

A die is thrown. Find the probability of getting :

i. an odd number.

ii. a perfect square.

iii. a number greater than 3.

Let S be the sample space.

Then S = {_____}

∴ n (S) = 6.

i. Let A be the event of getting an odd number.

Then A = {_____} ∴ n (A) = _____

P (A) = n (A)

n (S)

∴ P (A) = 3

6

=

1

2

.

ii. Let B be the event of getting a perfect square.

Then B = {_____} ∴ n (B) = _____

P (B) = n (B)

n (S)

∴ P (B) = 2

6

=

1

3

.

iii. Let C be the event of getting a number greater than 3.

Then C = {_____} ∴ n (C) = _____​

Answer 1

Answer:

probability of getting odd number =

$\frac{3}{6} = \frac{1}{2}$

probability of getting perfect square =

$\frac{2}{6} = \frac{1}{3}$

probability of getting a number greater than 3 =

$\frac{3}{6} = \frac{1}{2}$