A die is thrown n(s)
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A die is thrown n (s) What is the probability that "6" comes up at least once in the n throws?
Step-by-step explanation:
This is a Binomial Distribution problem.
Probability of success (that is “6” comes up) in a trial = 1/6
Probability of failure in a trial = 1 - 1/6 = 5/6
Therefore, probability of failure in all n trials = (5/6)^n
Probability of at least one success = 1 - Probability of failure in all n trials
= 1 - (5/6)^n
hope it helps....
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