Question

a die is thrown once .find the probability of getting (1) perfect square (2)a prime number

Answer 1

Answer:

1. $\frac{1}{3}$
2. $\frac{1}{2}$

Step-by-step explanation:

1. perfect square numbers are 1 and 4. so, p(e) =
2. $\frac{1}{3}$
3. prime numbers are 2,3,5. So, p(e) =
4. $\frac{1}{2}$

Answer 2

Given,

A die is thrown so total outcomes  = 6

To Find,

The probability of getting a perfect square =?

The probability of getting a prime number =?

Solution,

Outcomes when die is thrown  = 1, 2, 3, 4, 5, 6

Number of perfect squares between  1 - 6 = 2 [1 , 4]

Probability  = Favourable outcomes / Total outcomes

Therefore,

The probability of getting a perfect square = 2 / 6 = 1 / 3

Number of prime numbers between  1 - 6 = 3 [2, 3, 5]

The probability of getting a prime number = 3 / 6 = 1 / 2

Hence, the probability of getting a perfect square and a prime number is 1/3 and 1/2 respectively.