Question

A die is thrown once . find the probability of getting 1) a prime number 2) a number lying between 2 and 6 3) an odd number​

Answer 1

Explanation:

1. Number of favourable outcomes=3{2,3,5}

Total number of outcomes=6

hence, The probability of getting a prime number= 3/6=1/2

2. Total numbers lying between 2and 6=3{3,4,5}

hence, The probability of getting a number lying between 2and 6= 3/6=1/2

3. Total odd numbers= 3{1,3,5}

hence, The probability of getting an odd number=3/6=1/2

Hope it helps you........