Question

a die is thrown once find the probability of getting (1) a prime number (2) a number lying between 2 and 6​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Sample space ={ 1,2,3,4,5,6}

i) P(Prime number)=

Number of prime numbers/Sample space

P(Prime Number)=

$\frac{3}{6} = \frac{1}{2}$

ii) P(Number lying between 2 and 6)=

$\frac{3}{6} = \frac{1}{2}$

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