a die is thrown once .find the probability of getting (1)a prime number (2) a multiple of 3
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p(e)=possible outcomes/total outcomes
1) p(e)=1/2
2). p(e)=1/3
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Answer:
Total Outcome = ( 1,2,3,4,5,6)
Prime number = 2,3,5
P( a prime no) = 3/6=1/2
Multiple of 3 = 3, 6
P (multiple of 3 ) = 2/6 =1/3
Step-by-step explanation:
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