Question

A die is thrown once. Find the probability of getting
(1) a prime number, (m) a number lying between 2 and 6; (i) an odd number
​

Answer 1

Possible numbers of events on throwing a dice = 6 Numbers on dice = 1,2,3,4,5 and 6 (i) Prime numbers = 2, 3 and 5 Favourable number of events = 3 Probability that it will be a prime number = 3/6 = 1/2 (ii) Numbers lying between 2 and 6 = 3, 4 and 5 Favourable number of events = 3 Probability that a number between 2 and 6 = 3/6 = 1/2 (iii) Odd numbers = 1, 3 and 5 Favourable number of events = 3 Probability that it will be an odd number = 3/6 = 1/2Read more on Sarthaks.com - https://www.sarthaks.com/5533/thrown-once-find-probability-getting-prime-number-number-lying-between-and-iii-odd-number

Answer 2

HI MATE HERE IS YOUR ANSWER

1 . A probability of getting a prime number is : { 1,2,3,5}

no. of success by no. of total outcome

4 by 6 = 2 by 3

2. A number lying between two and six are { 3,4,5}

3. An odd number { 3,5}

HOPE THIS ANSWER HELPS YOU

PLEASE MARK ME AS YOUR BRAINLIST