Question

A die is thrown once . Find the probability of getting a number which has a least 2 factors

Answer 1

Answer:

Step-by-step explanation:

Sample space

1,2.3.4.5.6

4=2*2

6=2*3

P(least 2 factors) =2/6=1/3

I hope this helps you!!

Answer 2

Answer:

Probability = $\frac{1}{2}$

Step-by-step explanation:

If die is thrown once ,

then the

Total possible outcomes = {1,2,3,4,5,6}

Number of total possible outcomes (S) = 6

Favourable outcomes = {2,3,5}

/* which has least two factors means prime numbers */

Number of total possible outcomes (E) = 3

Probability of getting a number which has a least 2 factors

= $\frac{S}{E}$

= $\frac{3}{6}$

= $\frac{1}{2}$

Therefore,

Probability = $\frac{1}{2}$

•••••