A die is thrown once. Find the probability of getting a number which has at least 2 factors.
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Answered by
6
Hey friend!!!
Here's ur answer...
===========================
Possible outcomes :
1, 2, 3, 4, 5, 6
Total number of outcomes = 6
Numbers having at least 2 factors are : 2, 3, 4, 5, 6.
Probability of getting such number = 5/6
==============================
Hope it may help you....
Thank you :) :))
Here's ur answer...
===========================
Possible outcomes :
1, 2, 3, 4, 5, 6
Total number of outcomes = 6
Numbers having at least 2 factors are : 2, 3, 4, 5, 6.
Probability of getting such number = 5/6
==============================
Hope it may help you....
Thank you :) :))
tamannachahal:
thank you very much i just wanted to check as i got confused in it
Answered by
12
Hey there!
Sample space of a die = { 1 , 2 , 3 ,4 , 5 , 6 }
1 has only one factor .
2 ,3,5has two factors .
4 has 3 factors.
6 has 4 factors.
So, { 2 , 3 , 4 , 5 ,6 } have at least 2 factors.
Probability of getting a number which has at least 2 factors = 5/6 .
Hope helped!
Sample space of a die = { 1 , 2 , 3 ,4 , 5 , 6 }
1 has only one factor .
2 ,3,5has two factors .
4 has 3 factors.
6 has 4 factors.
So, { 2 , 3 , 4 , 5 ,6 } have at least 2 factors.
Probability of getting a number which has at least 2 factors = 5/6 .
Hope helped!
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