Question

A die is thrown once find the probability of getting a factor of 12

Answer 1

Answer:

1,2,3,4,6,12 it has 6 factors...

Answer 2

Given:

A die is thrown.

To Find:

The probability of getting a factor of 12.

Solution:

The total outcomes when a die is thrown are 1, 2, 3, 4, 5, and 6.

The favorable outcomes are 1, 2, 3, 4, 6.

Let $n(E)$ presents the number of total outcomes and $n(F)$ represents the favorable outcomes. Here, $n(E)=6$ and $n(F)=5$.

Also, let P be the even defined as the probability of getting a factor of 12 then its probability is,

$P(P)=\frac{n(E)}{n(F)} \\=\frac{5}{6}$

Thus, $\frac{5}{6}$ is the probability of getting a factor of 12 when a die is thrown.