A die is thrown once. Find the probability of getting a number less than 3.
Answers
SOLUTION :
Given : A die is thrown once .
A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.
If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6
Number of possible outcomes are = 6
Let E = Event of getting a number less than 3
Number less than 3 on a die are : 1, 2
Number of outcome favourable to E = 2
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 2/6 = 1/3
Hence, the required probability of getting a number less than 3, P(E) = 1/3
HOPE THIS ANSWER WILL HELP YOU…
Answer:
SOLUTION :
Given : A die is thrown once .
A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.
If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6
Number of possible outcomes are = 6
Let E = Event of getting a number less than 3
Number less than 3 on a die are : 1, 2
Number of outcome favourable to E = 2
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 2/6 = 1/3
Hence, the required probability of getting a number less than 3, P(E) = 1/3