A die is thrown once, find the probability of getting a composite number
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3
Answer:
Step-by-step explanation:
It passibility is 1/3 because composite numbers in a dice are only 4 and 6
Answered by
4
let C be getting composite number
possible out comes
1,2,3,4,5,6
n(s)=6
n(c)=《4,6》
= 2
probability of getting a composite number
p(C)= n(c)/ n(s)
= 2/6
=1/3
possible out comes
1,2,3,4,5,6
n(s)=6
n(c)=《4,6》
= 2
probability of getting a composite number
p(C)= n(c)/ n(s)
= 2/6
=1/3
bhaikamil222:
Even batter than my answer
then what can I do
better not batter
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