A die is thrown once. Find the probability of getting:a)an odd numberb)a number greater than 4c)a number between 2 and 6.plz solve it....
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a) prob of getting odd no. = no. Of favorable outcomes / total outcomes
Prob = 3/6 = 1/2
b) no. Greater than 4 are 5 & 6.
Therefore, prob = 2/6 = 1/3
c) no. between 2 & 6 are 3,4 & 5.
Therefore, prob of getting them = 3/6 = 1/2.
Prob = 3/6 = 1/2
b) no. Greater than 4 are 5 & 6.
Therefore, prob = 2/6 = 1/3
c) no. between 2 & 6 are 3,4 & 5.
Therefore, prob of getting them = 3/6 = 1/2.
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