Question

A die is thrown once. find the probability of getting a prime number​

Answer 1

Answer:

here is your answer:-

Explanation:

a die is thrown once,

total no. of possible outcomes= 1,2,3,4,5,6 = 6

total no. of favourable outcome ( total no. of primes ) = 3 (2,3,5)

possibility of getting a prime number= total no. of favourable outcome/ total no. of possible outcomes

= 3/6

=1/2

ANSWER:- 1/2

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Answer 2

Answer:

Possible outcomes - 6

Prime no - 2,3,5 =3 prime no

Probability =

$3 \div 6 = 1 \div 2$

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