Question

- A die is thrown once. Find the probability of getting an even number greater then 4

Answer 1

Answer:

outcome chances=no. of trials/total trials

no. of trial = 1

total trial = 6

outcome 1/6

Answer 2

✿solution✿☘️

total outcomes are = 1, 2 ,3,4,5,6,

number of total outcomes = 6

number of even number greater than 4 = 1

now;

$getting \: of \: even \: number \: p(e) = \frac{number \: of \: favourable \: outcomes}{number \: of \: total \: outcomes}$

$p(e) = \frac{1}{6}$

hence p(e) = 1/6