A die is thrown once . Find the probability of getting at most 2
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The probability is 2/6.
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Probability = Favourable Obs / No.Of Obs
Favourable obs = (1,2) = 2
No.Of obs =(1,2,3,4,5,6) = 6
P(Of getting at most 2) = 2 / 6
P(Of getting at most 2) = 1/3
Favourable obs = (1,2) = 2
No.Of obs =(1,2,3,4,5,6) = 6
P(Of getting at most 2) = 2 / 6
P(Of getting at most 2) = 1/3
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