Question

A die is thrown once.Find the probability of getting at most 2​

Answer 1

no. of outcomes=6

favourable outcomes=2 {1,2}

therefore prob. =2/6=1/3

Answer 2

Hey!

P(E) = No. of favourable outcomes/ No. of total outcomes

Here,

No. of favourable outcomes = 2 (1 and 2)

No. of total outcomes = 6

P(at most 2) = 2/6

=1/3

Hope this helps ✌✌