Math, asked by X78, 8 months ago

- A die is thrown once. Find the probability of
getting :
(i) a prime number
(ii) a number greater than 3
(iii) a number other than 3 and 5
(iv) a number less than 6
(v) a number greater than 6.​

Answers

Answered by dalloway
4

Answer:

i)1/2

ii)1/2

iii)2/3

iv)5/6

v)0

Answered by anukeerthika34
3

Step-by-step explanation:

1.s=(1,2,3,4,5,6)

A =(2,3,5)

n(A)/n(s)=3/6=1/2

2.B =(4,5,6)

n(B)/n(S)=3/6=1/2

3.C=(1,2,4,6)

n(C)/n(s)=4/6=2/3

4.D=(1,2,3,4,5)

n(D)/n(S)=5/6

5.E=( )=a number greater than 6 empty

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