Question

A die is thrown once find the probability of getting (i) a even prime number. (ii) a number divisible by 2. (iii) a multiple of 3.
(Class 10 Maths Sample Question Paper)

Answer 1

Total number of outcomes when a die is thrown once = 6 (1,2,3,4,5,6)

(i) even prime number = 2
Number of favourable outcomes = 1

Probability(P)= Number of favourable outcomes/total number of outcomes

P(getting a even prime number)= ⅙

(ii) Numbers divisible by 2 are = 2,4 & 6
Number of favourable outcomes= 3

Probability(P)= Number of favourable outcomes/total number of outcomes

P(getting a even number divisible by 2)=3/6= ½

(iii) multiples of 3 are 3 and 6
Number of available outcomes = 2

Probability(P)= Number of favourable outcomes/total number of outcomes

P(getting a even multiple of 3)= 2/6= ⅓

HOPE THIS WILL HELP YOU...

Answer 2

Total outcomes=6( 1,2,3,4,5,6)

i). favourable outcomes= 1 ( only 2 is the even prime number in between 1 to 6)

hence probability of getting a even prime number=favourable outcomes/total outcomes

=1/6

ii). favourable outcomes=3( 2,4,6 are divisible by 2)

hence probability of getting a number which is divisible by 2= favourable outcomes/total outcomes

=3/6

=1/2

iii). favourable outcomes= 2( only 3 and 6 are the multiple of 3)

hence probability of getting a number which is the multiple of 3= favourable outcomes/total outcomes

=2/6

=1/3

HOPE IT HELPS !!

THANK YOU :)