Question

A die is thrown once. Find the probability of getting(i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.

Answer 1

Favourable number of outcomes = 1,2,3,4,5,6
(i) {2,3,5} = 3/6 = 1/2
(ii){3,4,5} = 3/6 = 1/2
(iii){1,3,5} = 3/6 = 1/2

Answer 2

$\huge{\underline{\underline{\sf{\orange{SOLUTION:-}}}}}$

$\sf{\underline{\red{Answer-}}}$

• $\sf \: Prime \: Number = \frac{1}{2}$

• $\sf Number \: Lying \: between \: 2 \: and \: 6 = \frac{1}{2}$

• $\sf \: An \: Odd \: Number= \: \frac{1}{2}$

$\sf{\underline{\red{We\:Have\:To\:Find-}}}$

• (i) A prime number.

• (ii) A number lying between 2 and 6.

• (iii) An odd number.

$\sf{\underline{\red{Formula\:used\: here-}}}$

$\bigstar \: \: \: \: \boxed {\sf\: {P= \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes}}}$

$\sf{\underline{\red{Explanation-}}}$

$\sf \: Possible \: numbers \: of \: Outcomes\:While \: throwing \: a \: dice=6$

$\sf \: Numbers \: on \: a \: dice \: =1,2,3,4,5 \: and \: 6$

⠀⠀

$\bf\orange{A \: Prime \: Number - }$

⠀⠀

$\sf \: Prime \: numbers \: we \: can \: get= 2,3 \: and \: 5$

$\sf \: Number \: of \: favourable \: outcome=3$

$\sf \: Probability \: of \: being \: prime \: number \: = \frac{3}{6} = \frac{1}{2}$

⠀⠀

$\bf\orange{A \: number \: lying \: between \: 2 \: and \:6- }$

⠀⠀

$\sf \:Numbers \: we \: can \: get= 3, \:4 \: and \: 5$

$\sf \: Number \: of \: favourable \: outcome=3$

$\sf \: Probability \: of \: number\: between \: 2 \: and \: 6 \: = \frac{3}{6} = \frac{1}{2}$

⠀⠀

$\bf\orange{ An \: Odd\: number - }$

⠀⠀

$\sf \:Odd \: Numbers \: we \: can \: get= 1, \: 3\: and \: 5$

$\sf \: Number \: of \: favourable \: outcome=3$

$\sf \: Probability \: of \: being \: an \: odd \: number \: = \frac{3}{6} = \frac{1}{2}$