Math, asked by swastidt2556, 1 year ago

A die is thrown once. Find the probability of getting :i) A number divisible by 3.ii) Prime numbers.iii) Neither 2 nor 4.

Answers

Answered by Anonymous
18

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Answer in the attachment☺



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Answered by imhkp4u
14

Answer:


Step-by-step explanation:

According to the question,

If a dice is thrown once then the possible outcomes are as follows:

1,2,3,4,5 and 6.

i) The number divisible by 3 are as follows:

3 and 6.

P(divisibility by 3) = 2/6 = 1/3. [Ans]

ii)The prime numbers are as follows:

2,3 and 5

P(prime numbers) = 3/6 = 1/2. [Ans]

iii) The numbers apart from 2 or 4 are 1,3,5 and 6.

P(neither 2 nor 4) = 4/6 = 2/3. [Ans]

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