A die is thrown once. Find the probability of getting :i) A number divisible by 3.ii) Prime numbers.iii) Neither 2 nor 4.
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Step-by-step explanation:
According to the question,
If a dice is thrown once then the possible outcomes are as follows:
1,2,3,4,5 and 6.
i) The number divisible by 3 are as follows:
3 and 6.
P(divisibility by 3) = 2/6 = 1/3. [Ans]
ii)The prime numbers are as follows:
2,3 and 5
P(prime numbers) = 3/6 = 1/2. [Ans]
iii) The numbers apart from 2 or 4 are 1,3,5 and 6.
P(neither 2 nor 4) = 4/6 = 2/3. [Ans]
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