Question

a die is thrown once.find the probability of getting : (i)an even number, (ii)a multiple of 3 , (iii) a prime number

Answer 1

(1)aneven number=tOtal even numbers/total outcomes
total even numbers=3
total outcomes=6
probability of getting even numbers=3/6=1/2
(2)amultiple of 3
multiples of 3=2
total outcomes=6
so probability of getting multiples of 3 is=2/6=1/3
(3)total prime numbers =3
total no of outcomes =6
so probability of getting prime number is 3/6=1/2

Answer 2

1. Total no. of events =6

No. of possible events=3 (2,4,6)

P(e)=3/6 =1/2

2. Total no. of events =6

No. of possible events=2 (3,6)

P(e)=2/6 =1/3

3.Total no. of events =6

No. of possible events=3

P(e)=3/6 =1/2

Hope it helps...