A die is thrown once .find the probability of getting:number lying between 3 and 5
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Answer:
Between 3 and 5 there is just one number ie. 4
Total outcomes = 6
Hence required probability = 1/6
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total no of numbers is 6.
The no between 3 and 5 is 4.
If the dice is thrown once then the no 4 would also come once.
Therefore the probability =1/6
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