A die is thrown once.Find the probability of getting of getting a number which is either a multiple of 2 or of 3
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Answered by
1
Die is thrown
Total outcomes=6
P(getting an multiple of 2 or 3)= 5/6
Total outcomes=6
P(getting an multiple of 2 or 3)= 5/6
Answered by
2
n(2)= {2,4,6}
n(2)=3
P(2)= n(2) / n(S)
=3/6
=1/2
n(3)={3,2}
n(3)=(2)
P(3)=n(3)/n(S)
= 2/6
=1/3
n(2)=3
P(2)= n(2) / n(S)
=3/6
=1/2
n(3)={3,2}
n(3)=(2)
P(3)=n(3)/n(S)
= 2/6
=1/3
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